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An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in $$1\frac{2}{3}$$ hours, it must travel at a speed of:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{Distance}} = {240 \times 5} = 1200\,{\text{km}} \cr
& {\text{Speed}} = \frac{{{\text{Distance}}}}{{{\text{Time}}}} \cr
& {\text{Speed}} = \frac{{1200}}{{ {\frac{5}{3}} }}\,{\text{ km/hr}}\, \cr
& \left[ {{\text{We}}\,{\text{can}}\,{\text{write}}\,1\frac{2}{3}\,{\text{hours}}\,{\text{as}}\,\frac{5}{3}\,{\text{hours}}} \right] \cr
& \therefore {\text{Required}}\,{\text{speed}} \cr
& = {1200 \times \frac{3}{5}} \,{\text{ km/hr}} \cr
& = 720\,{\text{ km/hr}} \cr} $$
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Login=240*3=720 kmph