?
An ant moved for several seconds and covered 3 mm in the first second and 4 mm more in each successive second than its predecessor. If the ant had covered 1 mm in the first second and 8 mm more in each successive second, then the difference between the path it would cover during the same time and actual path would be more than 6 mm but less than 30 mm. find the time for which the ant moved (in seconds).
Answer & Solution
Correct Answer:
Option
B
3 + 7 + 11 + 15 + . . . . . (1)
1 + 9 + 17 + 25 + . . . . . (2)
The condition is satisfied for the 4 seconds in 2nd journey, ant covered 17 m more than 1st one.
Join the Discussion
Login to post a comment or share your explanation.
Login3+7+11+15+19+23
The second Pattern of movement is
1+9+17+25+33+41
it is evident that the difference in the net movement b/w the second pattern and the first pattern is more than 6 mm and less than 30mm for a movement of 4 seconds.
as,
in 4 seconds firstpattern= 3+7+11+15=36mm
second pattern= 1+9+17+25=52mm
difference =52-36=16mm which lies b/w 6 & 30
Ans is 4sec(B)