∠A + $$\frac{1}{2}$$ ∠B + ∠C = 140°, then ∠B is :
A. 50°
B. 80°
C. 40°
D. 60°
Answer: Option B
Solution(By Examveda Team)
According to question,∠A + $$\frac{1}{2}$$ ∠B + ∠C = 140° . . . . . . . . (i)
As we know that
∠A + ∠B + ∠C = 180° . . . . . . . . . (ii)
Compare equation (i) and (ii)
$$\frac{1}{2}$$ ∠B = 40°
∴ ∠B = 80°
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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