65.
The . . . . . . . . inhibition gives the following rate equation.
$$V = {{{V_{\max }}\left[ S \right]} \over {{K_m} + \left[ S \right]\left( {1 + {{\left[ S \right]} \over {{K_s}}}} \right)}}$$

69.
The following rate equation represents . . . . . . . . inhibition.
$$V = {{{V_{\max }}\left[ S \right]} \over {{K_m}\left( {1 + {I \over {{K_i}}}} \right) + \left[ S \right]}}$$

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