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61
$${\text{P}}{{\text{V}}^\gamma }$$  = Constant (where, $$\gamma = \frac{{{{\text{C}}_{\text{p}}}}}{{{{\text{C}}_{\text{v}}}}}$$  ) is valid for a/an __________ process.
Discuss
Answer & Solution
Answer: Option D
Solution:
For an adiabatic process, by first law of thermodynamics for an ideal gas under adiabatic conditions we can write :

\[\begin{array}{l} {C_V}dT = - PdV\\ \Rightarrow {C_V}dT = - \frac{{RT}}{{V\left( {dV} \right)}}\\ \Rightarrow \frac{{dT}}{T} = - \frac{R}{{{C_V}}}\frac{{dV}}{V}\\ \Rightarrow T{V^{\gamma - 1}} = {\rm{CONSTANT}}\\ {\rm{Or,\, }}P{V^\gamma } = {\rm{CONSTANT}} \end{array}\]
(Note : this equation can only be used for ideal gas and when the heat capacities are remaining constant)
62
In the reaction, represented by, 2SO2 + O2 ⇋ 2SO3; ΔH = -42 kcal; the forward reaction will be favoured by
Discuss
Answer & Solution
Answer: Option C
Solution:
Le Chatelier's principle says that for an exothermic reaction decrease in temperature favours the forward reaction and for a reaction if $$\Delta n < 0$$   the increase in pressure favours the forward reaction and for a reaction if $$\Delta n > 0$$   the increase in pressure favours the backward reaction. Since the given reaction is having $$\Delta n < 0$$   increase in pressure favours the forward reaction.
63
Trouton's ratio of __________ liquids is calculated using Kistyakowsky equation.
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Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
64
The heat capacities for the ideal gas state depend upon the
Discuss
Answer & Solution
Answer: Option B
Solution:
The heat capacities of ideal gas state is dependent only on temperature and usual relationship is given as : $${C_V} = a + bT + C{T^2} + ...$$
65
An ideal liquid refrigerant should
Discuss
Answer & Solution
Answer: Option C
Solution:
The given are opposite to the requirements of an ideal liquid refrigerants.
The ideal liquid refrigerant should have a sub atmospheric vapor pressure at the temperature in refrigerator coils and also should have high vapor pressure at the condenser temperature.
66
One mole of nitrogen at 8 bar and 600 K is contained in a piston-cylinder arrangement. It is brought to 1 bar isothermally against a resisting pressure of 1 bar. The work done (in Joules) by the gas is
Discuss
Answer & Solution
Answer: Option B
Solution:
Assuming ideal gas behavior the isothermal work done is given as :
\[\begin{array}{l} W = nRTln\frac{{{P_1}}}{{{P_2}}}\\ W = 1 * 8.321 * 2079\\ {\rm{So}},W = 10379,{\rm{nearly \, equal \, to }}\,W = 10373 \end{array}\]
67
Dry ice is
Discuss
Answer & Solution
Answer: Option C
Solution:
Dry ice is called as solid carbon dioxide. It will be below its triple point so on heating it directly gives off carbon dioxide gas.
68
Compressibility factor-reduced pressure plot on reduced co-ordinates facilitates
Discuss
Answer & Solution
Answer: Option A
Solution:
The main reason behind use of the reduced properties is it converges the different plots for different gases in to one gas since different type of gases having same reduced properties behave similarly.
69
Entropy of a substance remains constant during a/an __________ change.
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Answer & Solution
Answer: Option C
Solution:
Since only for a reversible process we have relation :
$$TdS = \delta Q$$
Since for an adiabatic process $$\delta Q = 0$$ $$ \,\,\, \Rightarrow $$ for an reversible adiabatic process $$TdS = 0.$$
So, entropy remains constant. Whereas for an irreversible adiabatic process $$TdS \geqslant 0.$$
Hence entropy goes on increasing for an irreversible adiabatic process.
70
Which of the following is a thermodynamic property of a system?
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Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board