ExamVeda
Login
Home
41
If $${{l_1}}$$ and $${{l_2}}$$ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w1 and w2 acting on strips parallel to $${{l_2}}$$ and $${{l_1}}$$ is
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
42
The minimum thickness of a flat slab is taken
Discuss
Answer & Solution
Answer: Option E
No explanation is given for this question. Let's Discuss on Board
43
Columns may be made of plain concrete if their unsupported lengths do not exceed their least lateral dimension
Discuss
Answer & Solution
Answer: Option B
Solution:
In RCC design, plain concrete columns are allowed only when the column is short and not subjected to significant bending.

According to standard design guidelines, a column can be made of plain concrete if its unsupported length does not exceed three times its least lateral dimension.

This limitation ensures that the column behaves primarily under axial compression and avoids buckling or instability.

If the length exceeds this limit, reinforcement becomes necessary to provide additional strength and stability.

Therefore, the correct condition is three times the least lateral dimension.
44
The number of treads in a flight is equal to
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
45
An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is
Discuss
Answer & Solution
Answer: Option A
Solution:
Given: Diameter of R.C.C. column D = 30 cm; 6 bars of 12 mm (1.2 cm) diameter; Axial load P = 40,000 kg

Gross area of column (Ag): (π/4)D2 = (π/4)(30)2 = 706.86 cm2

Area of one bar: (π/4)d2 = (π/4)(1.2)2 = 1.131 cm2 (approx.)

Total steel area (As): 6 × 1.131 = 6.786 cm2

Net concrete area (Ac): Ag − As = 706.86 − 6.786 = 700.07 cm2

Assume modular ratio (m): 15 (typical for RCC working stress method)

Transformed area carrying load: Ac + mAs = 700.07 + 15×6.786 = 801.86 cm2

Concrete stress (working): σc = P / (Ac + mAs) = 40,000 / 801.86 = 49.9 kg/cm2

Therefore, the stress is 49.9 kg/cm2 ⇒ Option A.
46
If d and n are the effective depth and depth of the neutral axis respectively of a singly reinforced beam, the lever arm of the beam, is
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
47
The allowable tensile stress in mild steel stirrups, reinforced cement concrete, is
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
48
In a singly reinforced beam, the effective depth is measured from its compression edge to
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
49
The steel generally used in R.C.C. work, is
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
50
The advantage of reinforced concrete, is due to
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board