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Arithmetic Reasoning - General Inteligence & Reasoning MCQ Questions and Answers

Learn Arithmetic Reasoning mcq questions and answers with easy and logical explanations - Arithmetic Reasoning is part of competitive reasoning mcq questions. Page-8 section-1

71
In a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads in the caravan, the number of keepers is
Discuss
Answer & Solution
Answer: Option D
Solution:
Let number of keepers be x. Then,
Total number of feet = 2 x 50 + 4 x 45 + 4 x 8 + 2x = 2x + 312.
Total number of heads = 50 + 45 + 8 + x= 103 + x.
Therefore (2x + 312) = (103 + x) + 224 or x = 15.
72
A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
Discuss
Answer & Solution
Answer: Option C
Solution:
Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e. till 5 p.m.
Clearly, in the next 1 hour i.e. till 6 p.m. the monkey ascends remaining 30 feet to touch the flag.
73
A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the ten's digit be x. Then, unit's digit = (11 - x).
So, number = 10x + (11 - x) = 9x + 11.
Therefore (9x + 11) + 27 = 10 (11 - x) + x ⇔ 9x + 38 = 110 - 9x ⇔ 18x = 72 ⇔ x = 4.
Thus, ten's digit = 4 and unit's digit = 7.
Hence, required number = 47.
74
An enterprising businessman earns an income of Re. 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. One the 10th day of business, his income is
Discuss
Answer & Solution
Answer: Option A
Solution:
Income on the first day = Re. 1.
Income on the 2nd day = Rs. (1x2) = Rs. 21.
Income on the 3rd day = Rs. (21 x 2) = Rs. 22 and so on. Thus, Income on the rath day = Rs. 2n-1.
Therefore Income on the 10th day = Rs. 29.
75
Nitin's age was equal to square of some number last year and the following year it would be cube of a number. If again Nitin's age has to be equal to the cube of some number, then for how long he will have to wait?
Discuss
Answer & Solution
Answer: Option B
Solution:
Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.
Such numbers are 25 and 27.
Thus, Nitin is now 26 years old. Since the next perfect cube after 27 is 64,
so required time period = (64 - 26) years = 38 years.
76
On Children's Day, sweets were to be equally distributed among 175 children in a school. Actually on the Children's Day, 35 children were absent and therefore each child got 4 sweets extra. Total how many sweets were available for distribution ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Step 1: Let the total number of sweets be = S.

Step 2: If all 175 children were present, each child would get = S ÷ 175 sweets.

Step 3: But 35 children were absent, so only 140 children were present.

Step 4: Now each child got = S ÷ 140 sweets.

Step 5: It is given that each child got 4 more sweets than originally planned.
So, (S ÷ 140) − (S ÷ 175) = 4

Step 6: Take LCM of denominators:
LCM of 140 and 175 = 700.
(S × (5 − 4)) ÷ 700 = 4
S ÷ 700 = 4

Step 7: Therefore, S = 700 × 4 = 2800

Final Answer: Total sweets available = 2800
77
Between two book-ends in your study are displayed your five favourite puzzle books. If you decide to arrange the five books in every possible combination and moved just one book every minute, how long would it take you ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Clearly, number of ways of arranging 5 books = 5 ! = 5 x 4 x 3 x 2 x 1 = 120.
So, total time taken = 120 minutes = 2 hours.
78
A placed three sheets with two carbons to get two extra copies of the original. Then he decided to get more carbon copies and folded the paper in such a way that the upper half of the sheets were on top of the lower half. Then he typed. How many carbon copies did he get?
Discuss
Answer & Solution
Answer: Option B
Solution:
Since the number of carbons is 2, only two copies can be obtained.
79
A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?
Discuss
Answer & Solution
Answer: Option B
Solution:
No. of digits in 1-digit page nos. = 1x9 = 9.
No. of digits in 2-digit page nos. = 2 x 90 = 180.
No. of digits in 3-digit page nos. = 3 x 900 = 2700.
No. of digits in 4-digit page nos. = 3189 - (9 + 180 + 2700) = 3189 - 2889 = 300.
Therefore No. of pages with 4-digit page nos. = (300/4) = 75.
Hence, total number of pages = (999 + 75) = 1074.