Arithmetic Reasoning - General Inteligence & Reasoning MCQ Questions and Answers

41

The number of boys in a class is three times the number of girls. Which one of the following numbers cannot represent the total number of children in the class ?

A) 48 B) 44 C) 42 D) 40

Discuss

Answer & Solution

Answer: Option C

Solution:

Let number of girls = x and number of boys = 3x.
Then, 3x + x = 4x = total number of students.
Thus, to find exact value of x, the total number of students must be divisible by 4.

42

A shepherd had 17 sheep. All but nine died. How many was he left with ?

A) Nil B) 8 C) 9 D) 17

Discuss

Answer & Solution

Answer: Option C

Solution:

'All but nine died' means 'All except nine died' i.e. 9 sheep remained alive.

43

In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. The total number of family members is

A) 3 B) 7 C) 10 D) 12

Discuss

Answer & Solution

Answer: Option C

Solution:

44

In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

A) 18 B) 36 C) 45 D) None of these

Discuss

Answer & Solution

Answer: Option D

Solution:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.
Then, .
R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.
Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 ⇔ 6R = 108 ⇔ R = 18.
Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

45

In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?

A) 62 B) 45 C) 28 D) 20

Discuss

Answer & Solution

Answer: Option D

Solution:

Total runs scored = (36 x 5) = 180.
Let the runs scored by E be x.
Then, runs scored by D = x + 5; runs scored by A = x + 8;
runs scored by B = x + x + 5 = 2x + 5;
runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.
So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.
Therefore 3x + 120 =180 ⇔ 3X = 60 ⇔ x = 20.

46

The total number of digits used in numbering the pages of a book having 366 pages is

A) 732 B) 990 C) 1098 D) 1305

Discuss

Answer & Solution

Answer: Option B

Solution:

Total number of digits
= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.

47

In a family, each daughter has the same number of brothers as she has sisters and each son has twice as many sisters as he has brothers. How many sons are there in the family ?

A) 2 B) 3 C) 4 D) 5

Discuss

Answer & Solution

Answer: Option B

Solution:

Let d and s represent the number of daughters and sons respectively.
Then, we have :
d - 1 = s and 2 (s - 1) = d.
Solving these two equations, we get: d = 4, s = 3.

48

At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ?

A) 60 B) 65 C) 90 D) None of these

Discuss

Answer & Solution

Answer: Option A

Solution:

49

Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?

A) 23 years B) 25 years C) 33 years D) 35 years

Discuss

Answer & Solution

Answer: Option A

Solution:

Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.
Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

50

A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

A) 12 B) 16 C) 18 D) 24

Discuss

Answer & Solution

Answer: Option B

Solution:

Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.