Find the equation of a circle whose diameter has end points (4, 3) and (-2, 1).
A. x2 + y2 - 2x - 4y = 3
B. x2 + y2 - 2x - 4y = 5
C. x2 + y2 - 6x + 2y = 3
D. x2 + y2 - 2x + 4y = 5
Answer: Option B
Solution (By Examveda Team)
Go through option,Points (4, 3) and (-2, 1) will satisfy the equation from option B, x2 + y2 - 2x - 4y = 5

Join The Discussion