51
A body of mass 2 kg is thrown upward with initial velocity of 20 m/s. After 2 seconds, its kinetic energy will be : (g = 10 m/s2)
Answer & Solution
Answer: Option
A
Solution:
We will use the following equation of motion to get the final velocity after 2 seconds.
V = u - gt
U = 20 m/s
g = 10
t = 2
V = 20 - 2 × 10
V = 20 - 20
V = 0
K.E = 1/2mv²
m = 2
v = 0
K.E = 0.5 × 0 × 2
= 0
V = u - gt
U = 20 m/s
g = 10
t = 2
V = 20 - 2 × 10
V = 20 - 20
V = 0
K.E = 1/2mv²
m = 2
v = 0
K.E = 0.5 × 0 × 2
= 0