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How many squares with side $$\frac{1}{2}$$ inch long are needed to cover a rectangle that is 4 feet long and 6 feet wide ?
Answer & Solution
Correct Answer:
Option
D
length of rectangle = 4ft = (4 ×12) inch = 48 inch
length of rectangle = 6ft = (6 ×12) inch = 72 inch
∴ Number of squares :
$$\eqalign{ & = \frac{{48 \times 72}}{{\frac{1}{2} \times \frac{1}{2}}} \cr & = 13824 \cr} $$
length of rectangle = 6ft = (6 ×12) inch = 72 inch
∴ Number of squares :
$$\eqalign{ & = \frac{{48 \times 72}}{{\frac{1}{2} \times \frac{1}{2}}} \cr & = 13824 \cr} $$
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