I is the incentre of ΔABC. If ∠ABC = 60°, ∠BCA = 80°, then the ∠BIC is
A. 90°
B. 100°
C. 110°
D. 120°
Answer: Option C
Solution (By Examveda Team)
According to question,
Given :
∠ABC = 60°
∠BCA = 80°
∠BIC = ?
∠BAC = 40°
∴ ∠BIC = 90° + $$\frac{1}{2}$$ × 40°
∠BIC = 110°
This Question Belongs to Arithmetic Ability >> Triangles
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