I is the incentre of ΔABC. If ∠ABC = 60°, ∠BCA = 80°, then the ∠BIC is

A. 90°

B. 100°

C. 110°

D. 120°

Answer: Option C

Solution(By Examveda Team)

According to question,

Given :
∠ABC = 60°
∠BCA = 80°
∠BIC = ?
∠BAC = 40°
∴ ∠BIC = 90° + $$\frac{1}{2}$$ × 40°
∠BIC = 110°