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If a distance of 50 m is covered in 1 minute, 90 m in 2 minutes and 130 m 3 minutes. Find the distance covered in 15th minute.
Answer & Solution
Correct Answer:
Option
A
Distance covered in 1 min = 50 m
Distance covered in 2 min = 90 m
Similarly, 1st min, 2nd min, 3rd min . . . . . 15th
Distance → 50 m + 90 m + 130 m + . . . . . . . .
By using A.P.
a = 50 m
d = (90 - 50) = 40 m
Tn = a + (n - 1)d
= 50 + (15 - 1) × 40
= 50 + 560
= 610 minutes
Distance covered in 2 min = 90 m
Similarly, 1st min, 2nd min, 3rd min . . . . . 15th
Distance → 50 m + 90 m + 130 m + . . . . . . . .
By using A.P.
a = 50 m
d = (90 - 50) = 40 m
Tn = a + (n - 1)d
= 50 + (15 - 1) × 40
= 50 + 560
= 610 minutes
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