If $$\delta $$ is the declination of the Polaris and $$\lambda $$ is the latitude of the place, the azimuth of the Polaris, is

A. $$\frac{{\cos \delta }}{{\cos \lambda }}$$

B. $$\frac{{\cos \left( {{{90}^ \circ } - \delta } \right)}}{{\cos \left( {{{90}^ \circ } - \lambda } \right)}}$$

C. $$\frac{{\sin \left( {{{90}^ \circ } - \delta } \right)}}{{\sin \left( {{{90}^ \circ } - \lambda } \right)}}$$

D. $$\frac{{\tan \left( {{{90}^ \circ } + \delta } \right)}}{{\tan \left( {{{90}^ \circ } + \lambda } \right)}}$$

Answer: Option A