If the area of the trapezium whose parallel sides are 6 cm and 10 cm is 32 sq. cm, then the distance between the parallel sides is :
A. 2 cm
B. 4 cm
C. 5 cm
D. 8 cm
Answer: Option B
Solution(By Examveda Team)
Let the required distance be x cmThen,
$$\eqalign{ & \Rightarrow \frac{1}{2} \times \left( {6 + 10} \right) \times x = 32 \cr & \Rightarrow x = 4\,cm \cr} $$
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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
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C. 44%
D. 46%
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