If the length of diagonal AC of a square ABCD is 5.2 cm, then the area of the square is :

Solution (By Examveda Team)

Area of the square :
$$\eqalign{ & = \left[ {\frac{1}{2} \times {{\left( {5.2} \right)}^2}} \right]{\text{ sq}}{\text{.cm}} \cr & {\text{ = }}\left( {\frac{1}{2} \times 27.04} \right){\text{ sq}}{\text{.cm}} \cr & = 13.52{\text{ sq}}{\text{.cm}} \cr} $$