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If the sum of numbers is 33 and their difference is 15, the smaller number is ?
Answer & Solution
Correct Answer:
Option
A
Let the numbers be x and y
Then,
$$x + y = 33.....(i)$$
And,
$$x - y = 15.....(ii)$$
Solving (i) and (ii), we get :
x = 24 , y = 9
∴ Smaller number = 9
Then,
$$x + y = 33.....(i)$$
And,
$$x - y = 15.....(ii)$$
Solving (i) and (ii), we get :
x = 24 , y = 9
∴ Smaller number = 9
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