In a ΔABC, ∠A + ∠B = 75° and ∠B + ∠C = 140°, then ∠B is:
A. 40°
B. 35°
C. 50°
D. 45°
Answer: Option B
Solution (By Examveda Team)
∠A + ∠B = 75° . . . . . . (i)∠B + ∠C = 140° . . . . . (ii)
(we know)
∠A + ∠B + ∠C = 180° . . . . . . (iii)
from equation (i) & (iii)
∠C = 105° . . . . . . . . . . . . . . . (iv)
from equation (ii) & (iv)
∠B = 35°
This Question Belongs to Arithmetic Ability >> Triangles
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