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In ΔABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.
Answer & Solution
Correct Answer:
Option
B
According to question,
Given :
∠A + ∠B = 65°
∠B + ∠C = 140°
We know that
∠A + ∠B + ∠C = 180°
∠C = 180° - (∠A + ∠B)
∠C = 180° - 65°
∠C = 115°
∠B = 140° - 115°
∠B = 25°
Given :
∠A + ∠B = 65°
∠B + ∠C = 140°
We know that
∠A + ∠B + ∠C = 180°
∠C = 180° - (∠A + ∠B)
∠C = 180° - 65°
∠C = 115°
∠B = 140° - 115°
∠B = 25°
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