In ΔABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.
A. 40°
B. 25°
C. 35°
D. 20°
Answer: Option B
Solution(By Examveda Team)
According to question,Given :
∠A + ∠B = 65°
∠B + ∠C = 140°
We know that
∠A + ∠B + ∠C = 180°
∠C = 180° - (∠A + ∠B)
∠C = 180° - 65°
∠C = 115°
∠B = 140° - 115°
∠B = 25°
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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