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Latent heat absorbed by 1 lb of water at 212 F...

This question belongs to Chemical Engineering Heat Transfer
Heat Transfer
?

Latent heat absorbed by 1 lb of water at 212°F, when it is changed to steam at 212°F, may be around __________ BTU.

Answer & Solution
Correct Answer: Option A
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2 Comments
Atanu Chatterjee
Atanu Chatterjee 1 year ago
The correct answer is:

B. 970

Explanation:
Latent heat of vaporization is the amount of heat required to convert a liquid into vapor without a change in temperature.

For water at 212°F (100°C) and standard atmospheric pressure:

The latent heat of vaporization ≈ 970 BTU/lb

This is the heat required to convert 1 lb of water at 212°F into 1 lb of steam at 212°F.

Other Options:
A. 180 BTU → This is the sensible heat to raise water from 32°F to 212°F.

C. 3.97 BTU → Irrelevant value.

D. None of these → Incorrect, since B is valid.

✅ Final Answer: B. 970
Waqas Faizan
Waqas Faizan 2 years ago
The latent heat of vaporization (also known as enthalpy of vaporization) for water at atmospheric pressure (212°F) is approximately 970 BTU per pound. so Answer is B
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