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O is the incentre of ΔABC and ∠A = 30°, then ∠BOC is
Answer & Solution
Correct Answer:
Option
B
According to question,
Given:
∴ ∠BOC = 90° + $$\frac{1}{2}$$ ∠A
∠BOC = 90° + $$\frac{1}{2}$$ × 30°
∠BOC = 90° + 15°
∠BOC = 105°
Given:
∴ ∠BOC = 90° + $$\frac{1}{2}$$ ∠A
∠BOC = 90° + $$\frac{1}{2}$$ × 30°
∠BOC = 90° + 15°
∠BOC = 105°
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