Reynold's analogy states that (where St = Stanton number f =...

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Reynold's analogy states that (where, St = Stanton number, f = friction factor)

A. $${\text{St}} = \frac{{\text{f}}}{2}$$

B. $${\text{St}} = \frac{{\text{f}}}{4}$$

C. St = 4f

D. $${\text{St}} = {{\text{f}}^{\frac{1}{2}}}$$

Answer: Option A

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