The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel ?

A. 850 ft

B. 950 ft

C. 1200 ft

D. 1450 ft

Answer: Option C

Solution(By Examveda Team)

Let the rear wheel make x revolutions
Then, the front wheel makes (x + 5) revolutions
(x + 5) × 40 = 48x
⇒ 8x = 200
⇒ x = 25
Distance travelled by the cart :
= (48 × 25) ft
= 1200 ft