The height of a solid right circular cylinder is 6 metres and three times the sum of the area of its two end faces is twice the area of its curved surface. The radius of its base (in metre) is

Solution (By Examveda Team)

Height of cylinder h = 6 metre
Let radius of cylinder = r metre
∴ curved surface area = 2πrh
Area of end face = πr²
⇒ Total area of two end faces
⇒
⇒ 2πr²
Given that 3 × 2πr² = 2 × 2πrh
3r = 2h
r = 4 cm
∴ Radius of base = 4 cm