The length and breadth of the floor of the room are 20 feet and 10 feet respectively. Square tiles of 2 feet length of different colours are to be laid on the floor. Black tiles are laid in the first row on all sides. If white tiles are laid in the one-third of the remaining and blue tiles in the rest, how many blue tiles will be there ?
A. 16
B. 24
C. 32
D. 48
E. None of these
Answer: Option A
Solution(By Examveda Team)
Area left after laying black tiles :$$\eqalign{ & = \left[ {\left( {20 - 4} \right) \times \left( {10 - 4} \right)} \right]{\text{sq}}{\text{.ft.}} \cr & = 96\,{\text{sq}}{\text{.ft.}} \cr} $$
Area under white tiles :
$$\eqalign{ & = \left( {\frac{1}{3} \times 96} \right){\text{sq}}{\text{.ft.}} \cr & = 32\,{\text{sq}}{\text{.ft.}} \cr} $$
Area under blue tiles :
$$\eqalign{ & = \left( {96 - 32} \right){\text{sq}}{\text{.ft.}} \cr & = 64\,{\text{sq}}{\text{.ft.}} \cr} $$
Number of blue tiles :
$$\eqalign{ & = \frac{{64}}{{\left( {2 \times 2} \right)}} \cr & = 16 \cr} $$
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
E. None of these
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
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