?
The radius of a sphere is reduced by 40%. By what percent will its volume decrease?
Answer & Solution
Correct Answer:
Option
D
$$ - 40\% \to \frac{{ - 2}}{5}$$
$$\eqalign{ & {\text{Decrease }}\% = \frac{{98}}{{125}} \times 100 \cr & = \frac{{98 \times 4}}{5} \cr & = \frac{{392}}{5} \cr & = 78.4\% \cr} $$
$$\eqalign{ & {\text{Decrease }}\% = \frac{{98}}{{125}} \times 100 \cr & = \frac{{98 \times 4}}{5} \cr & = \frac{{392}}{5} \cr & = 78.4\% \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login