The radius of the circum-circle of an equilateral triangle of side 12 cm is :
A. $$\frac{{4\sqrt 2 }}{3}$$
B. $$4\sqrt 2 $$
C. $$\frac{{4\sqrt 3 }}{3}$$
D. $$4\sqrt 3 $$
Answer: Option D
Solution (By Examveda Team)
Radius of circum-circle :$$\eqalign{ & = \frac{a}{{\sqrt 3 }} \cr & = \frac{{12}}{{\sqrt 3 }}\,cm \cr & = 4\sqrt 3 \,cm \cr} $$

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