The radius of the circum-circle of an equilateral triangle of side 12 cm is :

A. $$\frac{{4\sqrt 2 }}{3}$$

B. $$4\sqrt 2 $$

C. $$\frac{{4\sqrt 3 }}{3}$$

D. $$4\sqrt 3 $$

Answer: Option D

Solution(By Examveda Team)

Radius of circum-circle :
$$\eqalign{ & = \frac{a}{{\sqrt 3 }} \cr & = \frac{{12}}{{\sqrt 3 }}\,cm \cr & = 4\sqrt 3 \,cm \cr} $$