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The radius of the circum-circle of an equilateral triangle of side 12 cm is :
Answer & Solution
Correct Answer:
Option
D
Radius of circum-circle :
$$\eqalign{ & = \frac{a}{{\sqrt 3 }} \cr & = \frac{{12}}{{\sqrt 3 }}\,cm \cr & = 4\sqrt 3 \,cm \cr} $$
$$\eqalign{ & = \frac{a}{{\sqrt 3 }} \cr & = \frac{{12}}{{\sqrt 3 }}\,cm \cr & = 4\sqrt 3 \,cm \cr} $$
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