The ratio of milk and water in mixture of four containers are 5 : 3, 2 : 1, 3 : 2 and 7 : 4 respectively. In which container is the quantity of milk, relative to water, minimum ?

∴According to the question,
Container :
$$\eqalign{ & \,\,\,\,\,\,\,\,{\text{I}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{II}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{III}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{IV}} \cr & {\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}}\,\,\,{\text{M}}\,:\,{\text{W}} \cr & \,\,\,\,5:3\,\,\,\,\,\,\,\,\,\,\,2:1\,\,\,\,\,\,\,\,\,\,\,3:2\,\,\,\,\,\,\,\,\,\,7:4 \cr} $$

$$\eqalign{ & {\bf{Container}}\,\,({\text{I}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{5}{3} = 1.67 \cr & \cr & {\bf{Container}}\,\,({\text{II}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{2}{1} = 2 \cr & \cr & {\bf{Container}}\,\,({\text{III}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{3}{2} = 1.5 \cr & \cr & {\bf{Container}}\,\,({\text{IV}}): \cr & \frac{{{\text{Milk}}}}{{{\text{Water}}}} = \frac{7}{4} = 1.75 \cr} $$

∴ The quantity of milk relative to water minimum in container third.