The ratio of the areas of a square of side 6 cm and an equilateral triangle of side 6 cm is :

A. 3 : $$\sqrt 3 $$

B. 8 : $$\sqrt 3 $$

C. 6 : $$\sqrt 3 $$

D. 4 : $$\sqrt 3 $$

Answer: Option D

Solution(By Examveda Team)

Required ratio :
$$\eqalign{ & = \left( {6 \times 6} \right):\left( {\frac{{\sqrt 3 }}{4} \times 6 \times 6} \right) \cr & = 4:\sqrt 3 \cr} $$