The ratio of the areas of a square of side 6 cm and an equilateral triangle of side 6 cm is :
A. 3 : $$\sqrt 3 $$
B. 8 : $$\sqrt 3 $$
C. 6 : $$\sqrt 3 $$
D. 4 : $$\sqrt 3 $$
Answer: Option D
Solution (By Examveda Team)
Required ratio :$$\eqalign{ & = \left( {6 \times 6} \right):\left( {\frac{{\sqrt 3 }}{4} \times 6 \times 6} \right) \cr & = 4:\sqrt 3 \cr} $$
This Question Belongs to Arithmetic Ability >> Area
Join The Discussion