The sum of the radius of spheres A and B is

The sum of the radius of spheres A and B is 14 cm, the radius of A being larger than that of B. The difference between their surface areas is 112π. What is the ratio of the volumes of A and B?

A. 125 : 64

B. 64 : 27

C. 27 : 8

D. 8 : 1

Answer: Option B

Solution (By Examveda Team)

Let
Radius of A = R
Radius of B = r
R + r = 14 cm
4π(R² - r²) = 112π
(R - r)( R + r) = 28
14(R - r) = 28
R - r = 2
R = 8
r = 6
V → R³ : r³ = 4³ : 3³ = 64 : 27

A sphere and a hemisphere have the same volume. The ratio of their curved surface area is:

A. $${2^{\frac{3}{2}}}:1$$

B. $${2^{\frac{2}{3}}}:1$$

C. $${4^{\frac{2}{3}}}:1$$

D. $${2^{\frac{1}{3}}}:1$$

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The sum of the radius of spheres A and B is 14 cm, the radius of A being larger than that of B. The difference between their surface areas is 112π. What is the ratio of the volumes of A and B?

Solution (By Examveda Team)

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