Three times the first of three consecutive odd integers is 3 more than twice the third. The integer is :

A. 9

B. 11

C. 13

D. 15

Answer: Option D

Solution(By Examveda Team)

Let the three integers be x, (x + 2) and (x + 4)
Then,
Three times the first of three consecutive odd integers is 3 more than twice the third.
⇔ 3x = 2(x + 4) + 3
⇔ x = 11
∴ Third integer :
= x + 4
= 11 + 4
= 15