Three times the first of three consecutive odd integers is 3 more than twice the third. The integer is :
A. 9
B. 11
C. 13
D. 15
Answer: Option D
Solution (By Examveda Team)
Let the three integers be x, (x + 2) and (x + 4)Then,
Three times the first of three consecutive odd integers is 3 more than twice the third.
⇔ 3x = 2(x + 4) + 3
⇔ x = 11
∴ Third integer :
= x + 4
= 11 + 4
= 15
This Question Belongs to Arithmetic Ability >> Problems On Numbers
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