To obtain photographs of an area of 1000 m average elevation, on scale 1 : 30,000, with a camera of 30 cm focal length, the flying height is

Prana Krushna 1 year ago

Scale=f/H-h
1/30000=0.3/H-1000
H=10000m

Moksedur Rahman 2 years ago

10000m

Rose Ann 3 years ago

IT MUST BE 8,000. (1/30,000) ÷ ((30cm/100m)/H-1000m) = H = 8,000

Hanif Ullah 3 years ago

scale = f/H-h
f: focal length= 30cm=.3m
h=elevation height=1000m
H=height of flight=?
1/30000=.3/(H-1000)
H=8000

Mister Maskulado 4 years ago

1000 x 30 =30000
(30000 + 30000) / 10
60000/10
6000

Elnora Acoba 4 years ago

H=10000

Elnora Acoba 4 years ago

H=10000

Gaming Outlaw 5 years ago

1000/(3.3^( - 5 * 0.3))=5994.74

Gaming Outlaw 5 years ago

Ans 5994

Louie Jake 5 years ago

H= 10,000

Louie Jake 5 years ago

Isn't it H=10,000?

Sandya Rani 6 years ago

How to solve

Suga Shini 6 years ago

How to solve this problem ??Pls explain

Sakar Kc 6 years ago

Scale=1:30,000
Focal length=30cm=0.3m
Flying height =X+1000
We have ,
Scale =focal length of camera/flying height above ground level
(1/30000)=(0.3/X+1000)
X=8000 from my calculation

Chirag Raghu 6 years ago

No the answer is 10000
Explanation:
Scale= f/(H-h)
Where H is height of exposure station or plane
h - height of ground above mean sea level

1/30000= 30x10-2/(H-1000)
H= 30000x.3+ 1000
H= 10000

Kailash Meena 7 years ago

how to solve this problem ?
Please give explanation.