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Two trains are moving in the opposite direction at the speed of 48 km/hr and 60 km/hr respectively. The time taken by the slower train to cross a man sitting in the faster train is 12 seconds. What is the length of the slower train?

Answer & Solution
Correct Answer: Option D
$$\eqalign{ & {T_L} = \left( {48 + 60} \right) \times \frac{5}{{18}} \times 12 \cr & = 108 \times \frac{5}{3} \times 2 \cr & = 360 \cr} $$
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