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What is the weight of water contained in a conical vessel 21 cm deep and 16 cm in diameter ?
Answer & Solution
Correct Answer:
Option
B
Volume of water :
$$\eqalign{ & = \left( {\frac{1}{3} \times \frac{{22}}{7} \times 8 \times 8 \times 21} \right){\text{ c}}{{\text{m}}^3} \cr & = 1408{\text{ c}}{{\text{m}}^3} \cr & = \left( {\frac{{1408}}{{1000}}} \right)kg \cr & = 1.408\,kg \cr} $$
$$\eqalign{ & = \left( {\frac{1}{3} \times \frac{{22}}{7} \times 8 \times 8 \times 21} \right){\text{ c}}{{\text{m}}^3} \cr & = 1408{\text{ c}}{{\text{m}}^3} \cr & = \left( {\frac{{1408}}{{1000}}} \right)kg \cr & = 1.408\,kg \cr} $$
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