What would be the equation of the line, which intercepts x-axis at -5 and is perpendicular to the line y = 2x + 3?
A. x - 2y = -5
B. x + 2y = 5
C. x + 2y = -5
D. x - 2y = 5
Answer: Option C
Solution (By Examveda Team)
Slope of line y = mx + c is my = 2x + c, slope (m1) = 2
Lines are perpendicular to each other $${m_1} = \frac{{ - 1}}{{{m_2}}}$$
Slope of perpendicular line $$\left( {{m_2}} \right) = \frac{{ - 1}}{2}$$
on x axis y = 0
Equation of line which passes through (-5, 0)
(y - y1) = slope (m2)(x - x1)
y - 0 = $$\frac{{ - 1}}{2}$$ (x + 5)
2y = -x - 5
x + 2y = -5

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