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A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{Amount}}\,{\text{of}}\,{\text{milk}}\,{\text{left}}\,{\text{after}}\,{\text{3}}\,{\text{operations}} \cr
& = \left[ {40{{\left( {1 - \frac{4}{{40}}} \right)}^3}} \right]\,{\text{litres}} \cr
& = \left( {40 \times \frac{9}{{10}} \times \frac{9}{{10}} \times \frac{9}{{10}}} \right)\,{\text{litres}} \cr
& = 29.16\,{\text{litres}} \cr} $$
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LoginSo, second time we repeat the procedure, we'll have to take 4 litres of MILK out, not the milk and water solution. That means we'll have to take (4 + 4/9) litres of the solution i.e. 4litres milk + 4/9 litres water.
This way, the answer will be 28 only.