A vessel contains a 32 litre solution of acid and water in which the ratio of acid and water is 5 : 3. If 12 litres of the solution are taken out and $$7\frac{1}{2}$$ litres of water are added to it, then what is the ratio of acid and water in the resulting solution?

$$\eqalign{ & {\text{After removed 12L}} \cr & \,\,\,\,\,\,\,{\text{Acid}}\,\,\,\,\,\,\,\,:\,\,\,\,\,\,\,{\text{Water}} \cr & \Rightarrow 12 \times \frac{5}{8},\,12\, \times \frac{3}{8} \cr & \Rightarrow - 7.5,\, - 4.5 \cr & {\text{Acid}}\,\,\,\,\,\,\,\,\,\,{\text{Water}} \cr & \,\,\,{\text{20L }}\,\,\,\,\,\,\,\,\,\,{\text{ 12L}} \cr & - 7.5{\text{ }}\,\,\,\,{\text{ }} - 4.5 \cr & {\text{ }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }} + 7.5 \cr & \overline {\,12.5\,\,\,\,\,:\,\,\,\,\,\,15\,\,} \cr & \,\,\,\,\,\,5\,\,\,\,\,\,\,\,:\,\,\,\,\,\,\,\,6 \cr} $$