ABC is a triangle. The bisectors of the internal angle ∠B and external angle ∠C intersect at D. If ∠BDC = 50°, then ∠A is

A. 100°

B. 90°

C. 120°

D. 60°

Answer: Option A

Solution(By Examveda Team)

According to question,

Given :
∠D = 50°
∠BAC = 2∠BDC (property)
∴ ∠BAC = 2 × 50°
∠BAC = 100°