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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-10 section-2

Each section contains 100 MCQs on Percentage .
91
25% of the candidates who appeared in an examination failed and only 450 students qualify the exam. The number of students who appeared in the examination was :
Discuss
Answer & Solution
Answer: Option B
Solution:
Percentage of failed students = 25%
∴ Percentage of passed students
= (100 - 25)% = 75%
According to the question,
Total students :
= $$\frac{450}{75}$$ × 100 = 600
92
In an assembly election, a candidate got 55% of the total valid votes. 2% of the total votes were declared invalid. If the total number of voters is 104000, then the number of valid votes polled in favour of the candidate is :
Discuss
Answer & Solution
Answer: Option D
Solution:
Total votes = 104000
Total valid votes :
= 104000 × $$\frac{(100 - 2)}{100}$$
= 104000 ×$$\frac{98}{100}$$
= 101920
Votes polled in favour of the candidate :
= 101920 × $$\frac{55}{100}$$
= 56056
93
75 gm of sugar solution has 30% sugar in it. Then the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Sugar in original solution = $$\frac{{75 \times 30}}{{100}}$$  = 22.5 gm
Let m gm of sugar be mixed.
$$\therefore \frac{{22.5 + {\text{m}}}}{{75 + {\text{m}}}} \times 100 = 70$$
⇒ 2250+ 100m = 75 × 70 + 70m
⇒ 2250 + 100m = 5250 + 70m
⇒ 30m = 5250 - 2250 = 3000
⇒ m = $$\frac{{3000}}{{30}}$$  = 100 gm
94
In an examination, 1100 boys and 900 girls appeared, 50% of the boys and 40% of the girls passed the examination. The percentage of candidates who failed :
Discuss
Answer & Solution
Answer: Option D
Solution:
Total number boy = 1100 and girl = 900
Total number of boy fail (50%) = 550
Total number of girl fail ( 60%) = 540
Total failed candidates = (550 + 540) = 1090
Required percentage of failed candidates :
= $$\frac{1090}{(1100 + 900)}$$   × 100
= $$\frac{1080 × 100}{2000}$$
= 54.5%
95
Christy donated 10% of his income to an orphanage and deposited 20% of the remainder in his bank. If he has now Rs. 7200 left, what is his income :
Discuss
Answer & Solution
Answer: Option A
Solution:
Total income = 100x
10% deposit to orphange = 100x of 10% = 10x
Remain income 90x
Now 20% deposit to bank = 90x of 20% = 18x
Reamin income 90x - 18x = 72x
According to question
72x = 7200
⇒ x = $$\frac{7200}{72}$$ = 100
Income of Christy = 100 × 100 = 10000
96
The average marks obtained in a class of 50 students is 70%. The average of first 25 is 60% and that of 24 is 80%. What is the mark obtained by the last student ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Total Mark obtain by all 50 student = 50 × 70 = 3500
Total mark obtain by 1st 25 student = 25 × 60 = 1500
Total mark obtain by next 24 student = 24 × 80 = 1920
Mark obtain by last student = 3500 - (1500 + 1920) = 80
i.e 80% mark obtain by last student.
97
If 50% of (P - Q) = 30% of (P + Q) and Q = x% of P, then the value of x is :
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\frac{50}{100}$$(P - Q) = $$\frac{30}{100}$$(P + Q)
5P - 5Q = 3P + 3Q
2P = 8Q
P = 4Q
Put value of P in given equation
Q = P × $$\frac{x}{100}$$
Q = 4Q × $$\frac{x}{100}$$
x = 25
Hence required value of x = 25
98
If x% of a is the same as y% of b, then z% of b will be :
Discuss
Answer & Solution
Answer: Option B
Solution:
According to the question,
a × $$\frac{x}{100}$$ = b × $$\frac{y}{100}$$
xa = yb
⇒ b = $$\frac{xa}{y}$$
Put value of b in given equation,
z% of b = z% of $$\frac{xa}{y}$$ = $$\frac{zx}{y}$$ of a
99
A candidate who gets 20% marks in a examination fails by 30 marks but another candidate who gets 32% gets 42 marks more than the pass marks. Then the percentage of pass marks is :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the maximum marks = x
According to the question,
Case (i) pass marks = $$\frac{20x}{100}$$ + 30
Case (ii) pass marks = $$\frac{32x}{100}$$ - 42
Note : Pass marks would be same in both cases.
$$\frac{20x}{100}$$ + 30 = $$\frac{32x}{100}$$ - 42
$$\frac{12x}{100}$$ = 72
x = 600
Pass marks :
= 600 × $$\frac{20}{100}$$ + 30
= 150
Required percentage :
= $$\frac{150}{600}$$ × 100
= 25%
100
A man gives 50% of his money to his son and 30% to his daughter. 80% of the rest is donate to a trust. If he is left with 16000 now, how much money did he have in the beginning ?
Discuss
Answer & Solution
Answer: Option A
Solution:
x × $$\frac{20}{100}$$ × $$\frac{20}{100}$$ = 16000
x = 400000