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Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-10 section-1

Each section contains 100 MCQs on Speed Time and Distance .
91
A soldier fired two bullets at an interval of 335 seconds moving at a uniform speed V1. A terrorist who was running ahead of the soldier in same direction, hears the two shots at an interval of 330 seconds. If the speed of sound is 1188 km/h, then who is the faster and how much?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\frac{{{\text{Speed }}\,{\text{of }}\,{\text{sound}}}}{{{\text{Relative speed of soldier and terrorist}}}} = $$         $$\frac{{{\text{Time }}\,{\text{taken}}}}{{{\text{Difference }}\,{\text{in }}\,{\text{time}}}}$$
$$\frac{{1188}}{{\text{S}}} = \frac{{330}}{5}$$
Soldier = 18 km/h
92
A coolie standing on a railway platform observe that a train going in one direction takes 4 second to pass him. Another train of same length going in opposite direction takes 5 seconds to pass him. The time taken (in seconds) by two train to cross each other will be:
Discuss
Answer & Solution
Answer: Option C
Solution:
Let length of each train be X m, then
$$\eqalign{ & {S_1} = \frac{X}{4}\,{\text{and}} \cr & {S_2} = \frac{X}{5} \cr & {\text{Required time to cross each other,}} \cr & = {\frac{{2X}}{{ { {\frac{X}{4}} + {\frac{X}{5}} } }}} \cr & = \frac{{40}}{9}{\text{seconds}} \cr} $$
93
A dog start chasing to a cat 2 hour later. It takes 2 hours to dog to catch the cat. If the speed of the dog is 30 km/h. what is the speed of cat?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let speed of the cat be S km/h.
Time taken = $$\frac{{{\text{Distanced}}\,{\text{ advanced}}}}{{{\text{Relative}}\,{\text{ speed}}}}$$
2 = $$\frac{{2 \times {\text{S}}}}{{30 - {\text{S}}}}$$
S = 15 km/h
94
A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the original speed be S then,
Total time taken,
$$ {\frac{{36}}{{{\text{S}} - 6}}} + {\frac{{36}}{{{\text{S}} + 6}}} $$    = 8 hours
On solving the equation, we get
S = 12, -3
Then possible value of S = 12 km/h.
Thus, time taken by car at faster speed = $$\frac{{36}}{{12 + 6}}$$  = 2 hours
95
Roorkee express normally reaches its destination at 50 km/h in 30 hours. Find the speed at which it travels to reduce the time by 10 hours?
Discuss
Answer & Solution
Answer: Option C
Solution:
let required speed be S km/h
50 × 30 = S × 20
S = 75 km/h
96
A train 350 m long is running at the speed of 36 km/h. If it crosses a tunnel in 1 minute, the length of the tunnel in metres:
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the length of the tunnel be x m
Time = $$\frac{{{\text{Length of train}} + {\text{Length of tunnel}}}}{{{\text{Speed}}}}$$
60 = $$\frac{{350 + {\text{x}}}}{{10}}$$
$$ {{\text{Speed}} = \frac{{36 \times 5}}{{18}} = 10\,\,{\text{m/sec}}} $$
x = 250 meters
Therefore length of tunnel is 250 meters
97
If a 250 m long train crosses a platform of same length as that of the train in 25 seconds, then the speed of the train is:
Discuss
Answer & Solution
Answer: Option D
Solution:
Speed of train
= $$\frac{{{\text{length of the train}} + {\text{length of platform}}}}{{{\text{Time}}}}$$
= $$\frac{{250 + 250}}{{25}}$$
= 20 m/sec
= 72 km/h
98
A postman goes with a speed of 36 km/h what is the speed of postman in m/s?
Discuss
Answer & Solution
Answer: Option D
Solution:
Speed = 36 km/h = $$\frac{{36 \times 5}}{{18}}$$  = 10 m/s
99
Sabarmati express takes 18 seconds to pass completely through a station 162 m long and 15 seconds through another station 120 m long. The length of the train is :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let length of the train be x m
Speed of train,
$$\frac{{{\text{x}} + 162}}{{18}} = \frac{{{\text{x}} + 120}}{{15}}$$
x = 90 m
100
If two incorrect watches are set at 12:00 noon at correct time, when will both watches show the correct time for the first time given that the first watch gains 1 min in one hour and second watch looses 4 min in two hours.
Discuss
Answer & Solution
Answer: Option B
Solution:
First watch:
It shows correct time when it creates difference of 12 hours.
So, to create difference of 12 hour, time required = $$\frac{{60 \times 12}}{{24}}$$   = 30 days

Second watch:
It shows correct time when it creates difference of 12 hours.
So, to create difference of 12 hour, time required = $$\frac{{30 \times 12}}{{24}}$$   = 15 days
Now, LCM of 30 and 15 gives the time when they show correct time together. Thus, required time = 30 days, at same time.