Data Interpretation MCQ Questions and Answers - Table Chart

Number of candidates not clearing the exam from state A in 2007
$$\eqalign{ & = \left\{1.98\times\left(100 - 41\right)\%\right\}\text{lakhs} \cr & = \left(1.98\times\frac{59}{100}\right)\text{lakhs} \cr & = \left(\frac{116.82}{100}\times100000\right) \cr & = 116820 \cr} $$

Average number of candidates appearing from state D in 2007, 2008, 2009
$$\eqalign{ & = \frac{1.88+1.83+2.01}{3}\text{ lakhs} \cr & = \frac{5.72}{3}\text{ lakhs} \cr & = \frac{5.72\times100000}{3} \cr & = \frac{572000}{3} \cr & = 190666\frac{2}{3} \cr} $$

$$\eqalign{ & \text{Required ratio} \cr & = \frac{1.04\text{ lakhs}\times51\%}{1.11\text{ lakhs}\times32\%} \cr & = \frac{1.04\times51}{1.11\times32} \cr & = \frac{104\times51}{111\times32} \cr & = \frac{13\times17}{37\times4} \cr & = \frac{221}{148} \cr & = 221:148 \cr} $$

Number of candidates clearing the exam from states E and F together in 2006.
$$\eqalign{ & = \left(1.42\text{ lakhs}\times\frac{49}{100}\right)+\left(1.58\text{ lakhs}\times\frac{26}{100}\right) \cr & = \frac{\left(1.42\times49\right)+\left(1.58\times26\right)}{100}\text{ lakhs} \cr & = \frac{69.58+41.08}{100}\text{ lakhs} \cr & = \frac{110.66}{100}\times100000 \cr & = 110660 \cr} $$

Number of candidates clearing the exam from state D in
$$\eqalign{ & 2008 → \left(1.83\times\frac{60}{100}\right)\text{lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{1.83\times3}{5}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{5.49}{5}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = 1.10\text{ lakhs} \cr & 2009 → \left(2.01\times\frac{56}{100}\right)\text{lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{2.01\times14}{25}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{28.14}{25}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = 1.12\text{ lakhs} \cr} $$
In rest of the years it is clearly less.
So, it is maximum in the year 2009