Answer & Solution
= 5.9 × 100
= 590
Total Number of students in School E in 2006
= (5.5 + 3.6) × 100
= 9.1 × 100
= 910
$$\eqalign{ & \text{Required }\% \cr & = \left(\frac{590}{910}\times100\right)\% \cr & = \frac{5900}{91}\% \cr & = 64.8\% \cr & \approx 65\% \cr} $$