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This question belongs to Arithmetic Ability Calendar
Calendar
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December 9, 2001 is Sunday. What was the day on December 9, 1971?

Answer & Solution
Correct Answer: Option D
We know every year has 1 odd days
We know leap year has 2 odd days
Here, Number of Normal years= 22 and number of Leap years =8
So odd days =22+16 =38 i.e 3 odd days (remainder when 38 is divided by 7,i.e. 3)

Hence, it was a Thursday.
Examveda
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3 Comments
Debankur Biswas
Debankur Biswas 3 years ago
No it is not Tuesday. It's Thursday.
Sunday - 38 = Sunday - 3 = Thursday
Sethi
Sethi 4 years ago
It is D. (Thursday)
Azad Shankar
Azad Shankar 5 years ago
It's D ( Thursday)