What will be the day of the week 15th August, 2010?
A. Sunday
B. Monday
C. Tuesday
D. Friday
Answer: Option A
Solution(By Examveda Team)
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days.
Jan. Feb. March April Mayb June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
∴ 227 days = (32 weeks + 3 days) ≡ 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.
Given day is Sunday.
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Comments ( 4 )
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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
A. Sunday
B. Saturday
C. Friday
D. Wednesday
The number of odd days in 400 years will be ( 5 x 4 + 1) because 400 is itself a leap year and that is why it has one odd day extra. Thus odd days in 400 will be 0. This is same for every year which is a multiple of 100 and 400. Thus 1200 will also have odd days.
If first day is sunday then
7th day is saturday
Not sunday.
i did not understand. 9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days. how 2 leap years comes? and how can calculate odd days i.e 4
Plz give more discussions