Electromagnetic Theory MCQs Question and Answer in Engineering Physics

A. zero

B. 10πr²L

C. -5πr²L

D. -5πr²L²

A.

B.

C.

D.

A. 280.5 nF

B. 28.05 nF

C. 56.10 nF

D. 2.805 nF

A. Along the wire in the positive Z-axis

B. Radially inward $$\left( { - {\bf{\hat r}}} \right)$$

C. Radially outward $$\left( {{\bf{\hat r}}} \right)$$

D. Circumferential $$\left( \phi \right)$$

A. The force on Q₂ is along the direction from Q₂ to Q₁

B. The force on Q₂ is the same in magnitude as that on Q₁

C. The force on Q₁ is attractive

D. A point charge Q₃ = -3 nC, placed at the mid point between Q₁ and Q₂, experiences no net force

A. $$\frac{\pi }{{2a}}$$

B. $$\frac{{800}}{\pi }$$

C. $$\frac{{400}}{\pi }$$

D. $$\frac{{300}}{\pi }$$

A. there is no force acting on the dipole

B. there is no torque about the centre at O on the dipole

C. the dipole has minimum energy if it is in $${{{\bf{\hat e}}}_x}$$ direction

D. the force on the dipole is increased if the medium is replaced by another medium with larger dielectric constant

A. $${E_{0r}} = - \frac{3}{5}V/m,\,{E_{0t}} = \frac{7}{5}V/m$$

B. $${E_{0r}} = - \frac{1}{5}V/m,\,{E_{0t}} = \frac{8}{5}V/m$$

C. $${E_{0r}} = - \frac{2}{5}V/m,\,{E_{0t}} = \frac{8}{5}V/m$$

D. $${E_{0r}} = \frac{4}{5}V/m,\,{E_{0t}} = \frac{6}{5}V/m$$

A. $$4\pi P/3$$

B. $$ - 4\pi P/3$$

C. $$2\pi P$$

D. zero

A. The electric field at P is independent of q₂

B. The electric flux crossing the closed surface S is independent of q₂

C. The line integral of the electric field $$\overrightarrow {\bf{E}} $$ over the closed contour C depends on q₁ and q₂

D. $$\overrightarrow \nabla .\overrightarrow {\bf{E}} = 0$$  everywhere