If ABC is an equilateral triangle and D is a point of BC such that AD ⊥ BC, then

A. AB : BD = 1 : 1

B. AB : BD = 1 : 2

C. AB : BD = 2 : 1

D. AB : BD = 3 : 2

Answer: Option C

Solution(By Examveda Team)

According to question,

In equilateral triangle 'AD' bisects the BC in two equal parts.
Let side of equilateral triangle is 2 cm
$$\eqalign{ & \therefore \frac{{AB}}{{BD}} = \frac{2}{1} \cr & AB:BD = 2:1 \cr} $$