If ABC is an equilateral triangle and D is a point of BC such that AD ⊥ BC, then
A. AB : BD = 1 : 1
B. AB : BD = 1 : 2
C. AB : BD = 2 : 1
D. AB : BD = 3 : 2
Answer: Option C
Solution (By Examveda Team)
According to question,
In equilateral triangle 'AD' bisects the BC in two equal parts.
Let side of equilateral triangle is 2 cm
$$\eqalign{ & \therefore \frac{{AB}}{{BD}} = \frac{2}{1} \cr & AB:BD = 2:1 \cr} $$
This Question Belongs to Arithmetic Ability >> Triangles
Join The Discussion