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If ABC is an equilateral triangle and D is a point of BC such that AD ⊥ BC, then
Answer & Solution
Correct Answer:
Option
C
According to question,
In equilateral triangle 'AD' bisects the BC in two equal parts.
Let side of equilateral triangle is 2 cm
$$\eqalign{ & \therefore \frac{{AB}}{{BD}} = \frac{2}{1} \cr & AB:BD = 2:1 \cr} $$
In equilateral triangle 'AD' bisects the BC in two equal parts.
Let side of equilateral triangle is 2 cm
$$\eqalign{ & \therefore \frac{{AB}}{{BD}} = \frac{2}{1} \cr & AB:BD = 2:1 \cr} $$
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