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If ΔABC is an isosceles triangle with ∠C = 90° and AC = 5 cm then AB is:
Answer & Solution
Correct Answer:
Option
C
According to question,
Given: ∠C = 90°
BC = AC = 5 cm (Isosceles triangle)
By Pythagoras theorem
AB2 = AC2 + BC2
AB2 = 52 + 52
AB2 = 25 + 25
AB2 = 50
AB = 5$$\sqrt 2 $$ cm
Given: ∠C = 90°
BC = AC = 5 cm (Isosceles triangle)
By Pythagoras theorem
AB2 = AC2 + BC2
AB2 = 52 + 52
AB2 = 25 + 25
AB2 = 50
AB = 5$$\sqrt 2 $$ cm
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