In a triangle ABC, AB + BC = 12 cm, BC + CA = 14 cm and CA + AB = 18 cm. Find the radius of the circle (in cm) which has the same perimeter as the triangle

A. $$\frac{5}{2}$$

B. $$\frac{7}{2}$$

C. $$\frac{9}{2}$$

D. $$\frac{{11}}{2}$$

Answer: Option B

Solution(By Examveda Team)

According to question,

AB + BC = 12 cm
BC + CA = 14 cm
CA + AB = 18 cm
2(AB + BC + CA) = 44 cm
AB + BC + CA = $$\frac{{44}}{2}$$ cm
AB + BC + CA = 22 cm
Perimeter of triangle = 22 cm
Perimeter of triangle = Perimeter of circle
22 = 2πr
2 × $$\frac{{22}}{7}$$ × r = 22
r = $$\frac{7}{2}$$ cm