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In a triangle ABC, incentre is O and ∠BOC = 110°, then the measure of ∠BAC is:
Answer & Solution
Correct Answer:
Option
B
According to question,
Given : ∠BOC = 110°
∠BOC = 90° + $$\frac{1}{2}$$ ∠A
110° = 90° + $$\frac{{\angle A}}{2}$$
$$\frac{{\angle A}}{2}$$ = 20
∠A = 40°
Given : ∠BOC = 110°
∠BOC = 90° + $$\frac{1}{2}$$ ∠A
110° = 90° + $$\frac{{\angle A}}{2}$$
$$\frac{{\angle A}}{2}$$ = 20
∠A = 40°
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