In ΔABC, AD ⊥ BC and AD2 = BD × DC. The measure of ∠BAC is :
A. 75°
B. 90°
C. 45°
D. 60°
Answer: Option B
Solution(By Examveda Team)
AD2 = BD.DC
ΔADC ∼ ΔCAB (Property of a right angle Δ)
∠BAC = ∠ADC = 90°
Related Questions on Triangles
If ABC and PQR are similar triangles in which ∠A = 47° and ∠Q = 83°, then ∠C is:
A. 50°
B. 70°
C. 60°
D. 80°
In the following figure which of the following statements is true?
A. AB = BD
B. AC = CD
C. BC + CD
D. AD < Cd
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